for p being FinSequence of NAT
for i, j, k1, k2 being Element of NAT st i < len p & j < len p & 1 <= k1 & 1 <= k2 & k1 <= p . (i + 1) & k2 <= p . (j + 1) & (Sum (p | i)) + k1 = (Sum (p | j)) + k2 holds
( i = j & k1 = k2 )