let X be non empty TopSpace; :: thesis: for X1, X2, Y being non empty SubSpace of X holds
( ( X1,Y are_separated & X2,Y are_separated ) iff X1 union X2,Y are_separated )
let X1, X2 be non empty SubSpace of X; :: thesis: for Y being non empty SubSpace of X holds
( ( X1,Y are_separated & X2,Y are_separated ) iff X1 union X2,Y are_separated )
reconsider A2 = the carrier of X2 as Subset of X by Th1;
reconsider A1 = the carrier of X1 as Subset of X by Th1;
let Y be non empty SubSpace of X; :: thesis: ( ( X1,Y are_separated & X2,Y are_separated ) iff X1 union X2,Y are_separated )
reconsider C = the carrier of Y as Subset of X by Th1;
A1: Y is SubSpace of Y by Th2;
thus ( X1,Y are_separated & X2,Y are_separated implies X1 union X2,Y are_separated ) :: thesis: ( X1 union X2,Y are_separated implies ( X1,Y are_separated & X2,Y are_separated ) )
proof
assume ( X1,Y are_separated & X2,Y are_separated ) ; :: thesis: X1 union X2,Y are_separated
then A2: ( A1,C are_separated & A2,C are_separated ) ;
now :: thesis: for D, C being Subset of X st D = the carrier of (X1 union X2) & C = the carrier of Y holds
D,C are_separated
let D, C be Subset of X; :: thesis: ( D = the carrier of (X1 union X2) & C = the carrier of Y implies D,C are_separated )
assume that
A3: D = the carrier of (X1 union X2) and
A4: C = the carrier of Y ; :: thesis: D,C are_separated
A1 \/ A2 = D by A3, Def2;
hence D,C are_separated by A2, A4, Th41; :: thesis: verum
end;
hence X1 union X2,Y are_separated ; :: thesis: verum
end;
assume A5: X1 union X2,Y are_separated ; :: thesis: ( X1,Y are_separated & X2,Y are_separated )
( X1 is SubSpace of X1 union X2 & X2 is SubSpace of X1 union X2 ) by Th22;
hence ( X1,Y are_separated & X2,Y are_separated ) by A5, A1, Th71; :: thesis: verum